Y=(X^2+4x)9

Solution for Y=(X^2+4x)9 equation:

=(Y^2+4Y)9

We move all terms to the left:

-((Y^2+4Y)9)=0


We calculate terms in parentheses: -((Y^2+4Y)9), so:

(Y^2+4Y)9

We multiply parentheses

9Y^2+36Y

Back to the equation:

-(9Y^2+36Y)


We get rid of parentheses

-9Y^2-36Y=0

a = -9; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·(-9)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*-9}=\frac{0}{-18}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*-9}=\frac{72}{-18}
=-4
$